SOLUTION: I am not sure if this is the right section even but maybe you can help. "Determine the values of x for which the following expression will be undefined (i.e., the

Question 257756: I am not sure if this is the right section even but maybe you can help.
"Determine the values of x for which the following expression will be
undefined (i.e., the result is division by zero)."
____5_____
3x^2-75
Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
____5_____
3x^2-75
5/(3x^2-75)
5/(3*5^2-75)
5/(3*25-75)
5/(75-75)
5/0 ans.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Determine the values of x for which the following expression will be
undefined (i.e., the result is division by zero)."
____5_____
3x^2-75
:
What value of x make the denominator 0:
3x^2 - 75 = 0
3x^2 = 75; subtracted 75 from both sides
x^2 = 25; divided both sides by 3
Find the square root of both side
x = +/-
x = +5
x = -5
These values will make the denominator = 0, (undefined)

RELATED QUESTIONS
Again, I know I am in the wrong section... But can anyone help me solve the following... (answered by stanbon)
In a group of 14 students, there are 8 girls and 6 boys. a) Determine the number of... (answered by ewatrrr,stanbon)
hi, I have to determine if this function is even odd or neither...I believe is even... (answered by jim_thompson5910)
Dear math teacher, I am not sure why I am having a pretty hard time with... (answered by scott8148)
I'm not sure if this is the right section, but I really need help. Find: p(-3) if... (answered by ptaylor)
Not sure if this is the right section or not. Anyway, I'm struggling with... (answered by Fombitz)
I'm not sure I am in the right section, but can anyone help with the following problem? (answered by richard1234)
Directions: Give the total amount of the mix that results and the percent concentration... (answered by chessace)
I am not sure which Algebra section this question fits under. Hopefully someone can help... (answered by jim_thompson5910)