SOLUTION: Solve for all real roots (x-4)^2=36

Algebra.Com
Question 235302: Solve for all real roots
(x-4)^2=36
Found 2 solutions by jim_thompson5910, MathPro:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation.


Take the square root of both sides.


or Break up the "plus/minus" to form two equations.


or Take the square root of to get .


or Add to both sides.


or Combine like terms.


--------------------------------------


Answer:


So the solutions are or .
Answer by MathPro(14)   (Show Source): You can put this solution on YOUR website!
Good evening,
Your problem is: Solve for all real roots (x-4)^2=36
The first term is squared so let’s try to get rid of that by taking the square root of both sides of the equation:
(x-4)^[2(1/2)] = 36^1/2
x - 4 = 6
Let’s solve for x by adding 4 to both sides:
x – 4 + 4 = 6 + 4
x =10
Check the answer by substituting for x in the original equation:
(10-4)^2 = 36
36 = 36
The left-hand-side is equal to the right-hand-side, so the answer is correct.
Good Luck!
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