SOLUTION: 2x^4-15x^3+18x^2=0 Solve for x

Algebra.Com
Question 232291: 2x^4-15x^3+18x^2=0 Solve for x
Answer by eggsarecool(46)   (Show Source): You can put this solution on YOUR website!
Ok so first step is to factor out
This would give you
At this point you could factor the quadratic to become.
At this point if one term becomes 0 the whole thing does since anything times 0 is 0.
Now solve add 2x to both sides.
and now divide both sides by 2

For add x to both sides

And for take the square root of both sides
since

Your final answer for the problem would be
Now if you are not comfortable factoring the quadratic
You could use the quadratic formula instead
For the quadratic formula you take the numbers from
To give you
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=81 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 6, 1.5. Here's your graph:


And it is just has just been converted to a decimal by the computer.
So you would get from the quadratic formula, and then you would still get from . Same final answer, just two different methods.

RELATED QUESTIONS

SOLVE... (answered by Alan3354)
solve algebraically... (answered by stanbon)
Solve:... (answered by rothauserc)
x^2+18x-4=0 solve for... (answered by mananth)
solve for x.... (answered by vleith)
how do I solve,... (answered by stanbon)
Solve for x. x^4 - 15x^2-16 =... (answered by ikleyn)
1.how do I factor: 3x^4-24xy^3 2. solve all complex roots: 9x^4-18x^3+3x^2=16x (answered by edjones)
2x^3-x^2-18x+9=0 (answered by stanbon)