SOLUTION: Eliminate the imaginary number from the denominator of the following fraction 3i/7+2i

Algebra.Com
Question 206891: Eliminate the imaginary number from the denominator of the following fraction
3i/7+2i

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Eliminate the imaginary number from the denominator of the following fraction
3i/7+2i
----------
To do these, multiply by the conjugate.
3i/(7+2i)
= 3i(7-2i)/7+2i)*(7-2i)
= (21i + 6)/(49+4)
= (6+21i)/53

RELATED QUESTIONS

Eliminate the imaginary number from the denominator of the following fraction.. (answered by richwmiller)
Explain how complex numbers combine under the following operations: a. Addition... (answered by lynnlo)
Question: If Following Are The Solutions Of 2 Quadratic Equations Equation 1: Real... (answered by sabanasir)
Find the additive inverse of each number. (please) 15. -2 - 3i 16. 1 + 4i... (answered by Mathtut)
Find the additive inverse of each number 1. -2 - 3i 2. 1 + 4i 3. 5 - 3i 4. -7 + (answered by drk)
plot the complex number label the axis (7+12i)+(8-4i) simplify the following... (answered by richard1234)
How would you get "i" out of the denominator? Like in the problem... (answered by richard1234)
Write in the form of a+bi Division numerator 4-3i denominator... (answered by Nate)
How would I work the following problem? I need to rationalize the denominator of this... (answered by Fombitz)