SOLUTION: Hello I need help figuring out this equation involving radicals. I need to solve the equation and check for extraneious solutions. √a-1-5=1 I get a=-1 but I don't thin

Question 205199: Hello I need help figuring out this equation involving radicals. I need to solve the equation and check for extraneious solutions.
√a-1-5=1
I get a=-1 but I don't think that is right.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
√a-1-5=1
Assume the problem is:
= 1
Add 5 to both sides
= 1 + 5
= 6
Square both sides
a - 1 = 36
:
a = 36 + 1
a = 37
;
:
Check solution in original equation
= 1
= 1
6 - 5 = 1
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SOLUTION: Hello I need help figuring out this equation involving radicals. I need to solve the equation and check for extraneious solutions. &#8730;a-1-5=1 I get a=-1 but I don't thin