SOLUTION: 2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
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Question 202564: 2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Square both sides
Square the square root.
FOIL
Distribute
Combine like terms.
Get all the non-radical terms to one side
Combine like terms.
Combine the roots.
Divide both sides by -4.
Reduce
Square both sides
Square the square root
Square the right side
Multiply both sides by 4.
FOIL
Distribute
Subtract {{9x^2}}} from both sides.
Combine like terms.
Notice that the quadratic is in the form of where , , and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the possible solutions are or
However, if you plug in into the original equation, you'll get a contradiction.
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Answer:
So the only solution is
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