SOLUTION: the square root of 2n-8=-3 the steps i have are (2n-8)^2=(-3)^2 thats step one step two:2n-8=-9 then i added eight and got 2n=-1 which makes n= -1/2 so i plugged in -1/2 into

Question 196523This question is from textbook elementry and intermediate algebra
: the square root of 2n-8=-3
the steps i have are (2n-8)^2=(-3)^2 thats step one
step two:2n-8=-9 then i added eight and got
2n=-1 which makes n= -1/2 so i plugged in -1/2 into original equation and got
2(-1/2)-8= -9
that is wher i get lost because i do not know how to write my answer but my textbook says no real # solution???and my instructor said something about an extraneous solution i think i'm failing this course and will appreciate all help thanks tanya This question is from textbook elementry and intermediate algebra

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.

Square both sides

Square the square root to eliminate it

Square -3 to get 9 (NOT -9). Note: this is where you made a mistake

Add to both sides.

Combine like terms on the right side.

Divide both sides by to isolate .

So the possible solution is .

However, we need to check the possible solution.

Check:

Start with the given equation.

Plug in

Multiply

Reduce

Subtract

Take the square root of 9 to get 3

Since the both sides are clearly NOT equal, this means that is NOT a solution.

=============================

Answer:

So there are no solutions.

Note: an extraneous solution is a "solution" that is introduced in the intermediate steps but does NOT satisfy the original equation (the only equation we care about)
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