SOLUTION: Finding all real or imaginary solutions. I am not getting this. 3v^2 + 4v -1 = 0 So far I did this 3v^2 - 4v = 1 3v^2 -4v +4 = 1+4 after this I am confused. Please help.

Question 195226: Finding all real or imaginary solutions. I am not getting this.
3v^2 + 4v -1 = 0
So far I did this
3v^2 - 4v = 1
3v^2 -4v +4 = 1+4 after this I am confused. Please help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Finding all real or imaginary solutions. I am not getting this.
3v^2 + 4v -1 = 0
v = [-4 +- sqrt(16 - 4*3*-1)]/6
v = [-4 +- sqrt(28)]/6
v = [-4 +- 2sqrt(7)]/6
v = (-2/3) + (1/3)sqrt(7) or (-2/3) - (1/3)sqrt(7)
=======================================================
Cheers,
Stan H.
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