SOLUTION: Finding all real and imaginary solutions. Problem: w^2 = -225. I only found one solution. Did I do it correctly?

Algebra.Com
Question 195224: Finding all real and imaginary solutions.
Problem: w^2 = -225. I only found one solution. Did I do it correctly?

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


In a word, no. Prove it to yourself. Construct the binomial where is the root you calculated. Then square the binomial. If the result is different than then you can be assured there is another root.

The Fundamental Theorem of Algebra says that a polynomial of degree n has exactly n factors of the form (x - a). Each factor represents a root of the equation. The only way to have a single root for a quadratic is for the polynomial to be a perfect square -- and the only perfect square quadratic polynomials in a single variable are trinomials.

Where you went wrong is that when you took the square root of both sides of your equation, you forgot to consider both the positive and negative roots. Remember that if then or .

The roots of your equation are .

Now, if you multiply you will get

John


RELATED QUESTIONS

how do i find imaginary answers??? Find all real or imaginary solutions to each... (answered by tutorcecilia)
How do I find a real or imaginary solution to w^2 =... (answered by ankor@dixie-net.com,Alan3354)
Find all real and imaginary solutions w^2 = -225 Could someone please help me with... (answered by stanbon)
I really do not understand any of this stuff...can I get some help please? #80: find... (answered by RAY100)
Find all real or imaginary solutions to the eqyation.... (answered by checkley71)
80.)Find all real or imaginary solutions. use the method of your choice. w^2 = -225 (answered by checkley77)
Find the real or imaginary solutions... (answered by user_dude2008)
15x^2+10x-1=0 I was asked to find the discriminant. I said is 10x-1 and did it have 2... (answered by Earlsdon)
Find a real or imaginary solution 80.... (answered by Mathtut)