SOLUTION: Solve the equation. -5^3square root x-2=15 I worked it out to: ^3square root x-2=3 (^3square root x-2)^3=(-3)^3 x-2=-27 x=-25 Am I correct?

SOLUTION: Solve the equation. -5^3square root x-2=15 I worked it out to: ^3square root x-2=3 (^3square root x-2)^3=(-3)^3 x-2=-27 x=-25 Am I correct?

Algebra.Com

Question 190471This question is from textbook saxon algebra 2
: Solve the equation.
-5^3square root x-2=15
I worked it out to:
^3square root x-2=3
(^3square root x-2)^3=(-3)^3
x-2=-27
x=-25
Am I correct?
This question is from textbook saxon algebra 2

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

To the extent that you meant

Yes.

Next time you need to express a radical with an index, do it this way:

root(n,x) which would mean

-- yours here would have been

-5*root(3, x - 2)=15

John

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