SOLUTION: 1. (/ represents square root of) Simplify: (/5-3)(/5-1) 2. Also How far above the water would a submarine periscope have to be to locae a ship 3.5 mi away? The equation for the

Algebra ->  Algebra  -> Radicals -> SOLUTION: 1. (/ represents square root of) Simplify: (/5-3)(/5-1) 2. Also How far above the water would a submarine periscope have to be to locae a ship 3.5 mi away? The equation for the      Log On

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Question 186855: 1. (/ represents square root of)
Simplify: (/5-3)(/5-1)
2. Also How far above the water would a submarine periscope have to be to locae a ship 3.5 mi away? The equation for the distance in miles that the lookout can see is D=1.4/h, where h is the height in feet above the surface of the water.
Answer by vleith(2517) About Me  (Show Source):
You can put this solution on YOUR website!
%28sqrt%285%29+-+3%29%2A%28sqrt%285%29+-1%29
sqrt%285%29%2Asqrt%285%29+-+1%2Asqrt%285%29+-+3%2Asqrt%285%29+%2B+3
5+-+4%2Asqrt%285%29+%2B+3
8+-+4%2Asqrt%285%29
Also How far above the water would a submarine periscope have to be to locate a ship 3.5 mi away? The equation for the distance in miles that the lookout can see is D=1.4/h, where h is the height in feet above the surface of the water.
D=1.4%2Fh
3.5+=+1.4%2Fh
h+=+1.4%2F3.5
h+=+0.4 feet above the water