SOLUTION: Simplify. 3 over square root 7 - square root 2

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Question 183015This question is from textbook saxon algebra 2
: Simplify.
3 over square root 7 - square root 2
This question is from textbook saxon algebra 2

Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
3%2F%28sqrt%287%29-sqrt%282%29%29 Start with the given expression.


%283%28sqrt%287%29%2Bsqrt%282%29%29%29%2F%28%28sqrt%287%29-sqrt%282%29%29%28sqrt%287%29%2Bsqrt%282%29%29%29 Multiply both the numerator and denominator by sqrt%287%29%2Bsqrt%282%29



%283%28sqrt%287%29%2Bsqrt%282%29%29%29%2F%28%28sqrt%287%29%29%5E2-%28sqrt%282%29%29%5E2%29 FOIL. Note: the denominator is a difference of squares.



%283%28sqrt%287%29%2Bsqrt%282%29%29%29%2F%287-2%29 Square sqrt%287%29 to get 7. Square sqrt%282%29 to get 2


%283%28sqrt%287%29%2Bsqrt%282%29%29%29%2F%285%29 Combine like terms.


%283%2Asqrt%287%29%2B3%2Asqrt%282%29%29%2F%285%29 Distribute


So 3%2F%28sqrt%287%29-sqrt%282%29%29=%283%2Asqrt%287%29%2B3%2Asqrt%282%29%29%2F%285%29