SOLUTION: the problem is radical 3+2n + radical 2-2n =3, when i type radical it means the 3+2n and 2-2n are under the radical sign. i hope you can help me understand.

Question 182132This question is from textbook college algebra
: the problem is radical 3+2n + radical 2-2n =3, when i type radical it means the
3+2n and 2-2n are under the radical sign. i hope you can help me understand. This question is from textbook college algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the problem is radical 3+2n + radical 2-2n = 3,
:
+ = 3
:
= 3 -
square both sides:
3 + 2n = (3 - )^2
FOIL the right side
3 + 2n = 9 - 6 + (2-2n)
:
3 + 2n = 9 + 2 - - 2n
:
3 + 2n = 11 - - 2n
:
3 - 11 + 2n + 2n = -
:
4n - 8 = -
:
square both sides, FOIL the left side
16n^2 - 64n + 64 = 36(2-2n)
:
16n^2 - 64n + 64 = 72 - 72n
:
16n^2 - 64n + 72n + 64 - 72 = 0
:
16n^2 + 8n - 8 = 0
Simplify, divide by 8
2n^2 + n - 1 = 0
Factors to
(2n - 1)(n + 1) = 0
Two solutions:
n =
n = -1
:
:
Check both solution in original equation:
n = .5
+ = 3
+ = 3
+ = 3; a good solution
:
n = -1
+ = 3
+ = 3; also a good solution

RELATED QUESTIONS
what is the expression (2m^2n) 3/2 fraction in radical form (answered by Alan3354)

what is the expression in radical form... (answered by solver91311)

what is the expression(2m^2n)3/2 in radical form 1.)3sqrt4m^2n^2 2.)sqrt2m^6n^3... (answered by Boreal)

leave a non-perfect square under the radical sign: 3n^2-2n^2+8=89. how do I solve... (answered by jim_thompson5910)

HELP!!! PLEASE!!!! (3x^2 under the radical sign) + (2 outside radical sign 48x^2 under... (answered by uma)

solve: radical 6x-2=radical 2x+3 - radical 4x-1 i did not know what to use for the... (answered by jsmallt9)

How would i solve this equation in radical and decimal form... (answered by ReadingBoosters)

When 2 radical 3 is added to radical 27 the sum is 1. 2 radical 30 2. radical 39 3. 5... (answered by solver91311)

{{{sqrt(28n^2)}}} i know that the answer is 2n radical 7 but i dont know how to show the... (answered by mbarugel)