SOLUTION: Find the real solutions of each equation. Please help me solve this equation
{{{sqrt(2x+3)}}} - {{{sqrt(x+1)}}} = 1
Here's the steps I took:
1. {{{sqrt(2x+3)}}} = {{{sqrt(x+
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Question 181271This question is from textbook College Algebra Enhanced with Graphing Utilities, 5e
: Find the real solutions of each equation. Please help me solve this equation
- = 1
Here's the steps I took:
1. =
2. 2x+3=x+1+1+1
3. 2x+3= x+2+1
4. x-1=1
5. (x-1)^2=1(x+1)
6. x^2-2x+1=x+1
7. x^2-3x=0
8.(x-1)(x-2)=0
9. x=1, x=2
The answer in the book is -1 and 3
This question is from textbook College Algebra Enhanced with Graphing Utilities, 5e
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your first step was incorrect.
You absorbed the 1 on the right hand side under the radical but you can't do that.
x=3, x=-1
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