SOLUTION: Please help! I am really stuck q^2+6q-7=0
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Algebra: Radicals -- complicated equations involving roots
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Question 181006
:
Please help! I am really stuck
q^2+6q-7=0
Answer by
Alan3354(21583)
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You can
put this solution on YOUR website!
q^2+6q-7=0
-------------
That can be factored.
(q+7)*(q-1) = 0
If the product is zero, one of the binomials must be zero.
q+7 = 0
q = -7
------------
q-1 = 0
q = 1