SOLUTION: subtract
3 (cubert x^5y^7) - 8xy(cubert x^2 y^4)
Algebra.Com
Question 172446: subtract
3 (cubert x^5y^7) - 8xy(cubert x^2 y^4)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3 (cubert x^5y^7) - 8xy(cubert x^2 y^4)
------
= 3*x*y^2cubert(x^2y) - 8xy*ycubert(x^2y)
= (3xy^2-8xy^2)cubert(x^2y)
= -5xy^2*cubert(x^2y)
==============================
Cheers,
Stan H.
RELATED QUESTIONS
[SQRT(x + 7)] - 2[SQRT(x)] =-2
I know x = 9
but I am not sure how to get there.
How... (answered by Alan3354)
Please help
x+2= cubert(12x+8)
thank... (answered by Nate)
HELP A POOR GIRL OUT!
1. x/3SQRT(2x-3)-1/SQRT(2x-3)=1/3
2. CUBERT(2x3 - 24) = -x... (answered by ramkikk66)
how in the world do you do this? thanks!
SQRT(4a + 1) = 1
CUBERT(3x -... (answered by josgarithmetic)
Solve the following; don't forget to check for extraneous roots
CUBERT(2x3 - 24) = -x
(answered by Alan3354)
Simplify
CUBERT(-27)
(answered by macston)
[cubert(24.77)*sqrt(0.053)/forthrt(615)]^1/3 find... (answered by Cromlix)
Rewrite each function to make it easier to graph using a translation. Describe the... (answered by stanbon)
Simplify the following: Cuberoot of (64/x^21)
I have taken the cube root of both the top (answered by ankor@dixie-net.com)