SOLUTION: Not sure what is being asked. This is a homework assignment.
y=x^2 - 5x + 6
and y=-x^2 + 2x-1
Thanks.
Algebra.Com
Question 171705: Not sure what is being asked. This is a homework assignment.
y=x^2 - 5x + 6
and y=-x^2 + 2x-1
Thanks.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y=x^2 - 5x + 6
and y=-x^2 + 2x-1
----------------------
Let's assume the two quations are a system.
Substitute to get:
x^2 -5x + 6 = -x^2 + 2x -1
2x^2 - 7x +7= 0
Use the Quadratic formula to get:
x = [7 +- sqrt(49 -4*2*7)]/4
x = [7 +- sqrt(-7)]/4
x = [7 +- isqrt(7)]/4
-----------------------------
Hmmmmm?
If they are a system of equations they do not have a Real Number solution.
=======================
Cheers,
Stan H.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
It looks like they want you to factor the equations
Look at the constant term,
Notice that and
answer
----------------------
A good method is the "complete the square" method
Set to find the roots
Take 1/2 of the coefficient of , square it
and add it to both sides
First, though, add to both sides
Take the square root of both sides
The roots of the equation are:
and
The factors of the equation are
Note that the factors are just and
where and are the roots
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