SOLUTION: sqrt56+ sqrt126
Algebra.Com
Question 169550: sqrt56+ sqrt126
Answer by midwood_trail(310) (Show Source): You can put this solution on YOUR website!
sqrt{56} + sqrt{126} =
Break each sqrt separately.
sqrt{56} = sqrt{4} times sqrt{14}, where the square root of 4 is a perfect square.
sqrt{56} = 2(sqrt{14}).
=======================
sqrt{126} = sqrt{9} times sqrt{14}), where sqrt{9} is a perfect square.
sqrt{126} = 3(sqrt{14})
Now that we have the same radicand 14, we can add the radicals.
2(sqrt{14}) + 3(sqrt{14}) = 5(sqrt{14}) as the final answer.
============================================================
NOTE: We cannot break down sqrt{14} anymore because it is already in lowest terms.
RELATED QUESTIONS
3x-5/x+2=x-1/2x-1
6x^2-13x+5=x^2+x-2
5x^2-14x+7
-(-14)+or-sqrt(-14)^2-4(5)(7)/2(5)... (answered by jim_thompson5910)