SOLUTION: What is the exact value of this expression. sec^2 50°- tan^2 50°

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Question 169035: What is the exact value of this expression. sec^2 50°- tan^2 50°
Answer by nerdybill(5404) About Me  (Show Source):
You can put this solution on YOUR website!
One of the trigonometric identity is:
1+tan^2 u = sec^2 u
.
Here is a site w/trig identities:
http://www.sosmath.com/trig/Trig5/trig5/trig5.html
.
so, if we started with:
1+tan^2 u = sec^2 u
subtracting tan^2 u from both sides:
1 = sec^2 u - tan^2 u
.
Therefore:
sec^2 50°- tan^2 50° = 1