SOLUTION: I need to simplify: -5+ the square root of 3 divided by 1 - the square root of 2. I believe the first step would be to elimate the radical from the denomenator so I would multiply

Question 148951: I need to simplify: -5+ the square root of 3 divided by 1 - the square root of 2. I believe the first step would be to elimate the radical from the denomenator so I would multiply by square root of 2 on the bottom and top. From there I am stuck.
I thought it would be: -5+ square root of 3 times the square root of 2, divided by 1 - the square root of 2 time the square root of 2. Which equals: -5square root of 2 + square root of 6 divided by -1. Where am i going wrong?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I need to simplify: -5+ the square root of 3 divided by 1 - the square root of 2. I believe the first step would be to elimate the radical from the denomenator so I would multiply by square root of 2 on the bottom and top. From there I am stuck.
I thought it would be: -5+ square root of 3 times the square root of 2, divided by 1 - the square root of 2 time the square root of 2. Which equals: -5square root of 2 + square root of 6 divided by -1. Where am i going wrong?
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If you multiply by sqrt(2), you get
That won't help. The trick is to multiply thru by the "conjugate" of the DEN. In this case, it's
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