# SOLUTION: Consider the equation 4x^2 – 4x + 5 = 0. (i) Compute the discriminant, b2 – 4ac, and then state whether one real-number solution, two different real-number solutions, or two di

Algebra ->  Algebra  -> Radicals -> SOLUTION: Consider the equation 4x^2 – 4x + 5 = 0. (i) Compute the discriminant, b2 – 4ac, and then state whether one real-number solution, two different real-number solutions, or two di      Log On

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 Click here to see ALL problems on Radicals Question 147444: Consider the equation 4x^2 – 4x + 5 = 0. (i) Compute the discriminant, b2 – 4ac, and then state whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist. (ii) Use the quadratic formula to find the exact solutions of the equation. Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!4x^2 – 4x + 5 = 0 4x^2 + (-4)x + 5 = 0 ax^2 + bx + c = 0 a = 4 b = -4 c = 5 (i) Compute the discriminant, b2 – 4ac, and then state whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist. disc. > 0 ~ two real disc. = 0 ~ one real disc. < 0 ~ two imaginary (ii) Use the quadratic formula to find the exact solutions of the equation.