SOLUTION: Invisible numbers...Perform indicated operation. Write results in the form of a+bi 6 / 5-2i Six divided by five minus 2i. I started this problem by mutiplying the nume

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The whole idea is to get rid of any i's you see in the denominator. How do we do this?
Since we know that i*i = -1
We would like to apply this bit of info.
We need to find something to multiply the denominator such that we can rid ourselves of that i.
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So, if you started with:
.
6/(5-2i)
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Multiply numerator and denominator with (5+2i)
6/(5-2i) * (5+2i)/(5+2i)
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Looking at the denominator, we have:
(5-2i)(5+2i)
Applying "FOIL", we get (25 + 10i - 10i + 4)
notice the i's go away leaving just 29.
.
So, let's multiply out:
6/(5-2i) * (5+2i)/(5+2i)
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we get:
6(5+2i)/29
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(30+12i)/29