SOLUTION: I would really appreciate help on this problem. It is multiplying radicals. the square root of 3x^3 divided by the sqaure root of 4y^2 times the sqaure root of 9x^2 divided by

Question 142279: I would really appreciate help on this problem. It is multiplying radicals.
the square root of 3x^3 divided by the sqaure root of 4y^2 times the sqaure root of 9x^2 divided by the square root of 2y^4.
I thought that you multiplied the top and bottom by the bottom, which gets rid of the radical on the bottom, but it just isnt working out.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Do you mean like this???

I would put it together into one square root:

Simplify:

Put all the perfect square factors in the first square root, and leftover factors in the second square root:

Rationalize the denominator of the second fraction by multiplying inside the radical by .

Simplify:

For more help on square roots, please see my own user-friendly explanation by clicking on my tutor name "rapaljer" anywhere in algebra.com. Click on the second link on my homepage, which is "Basic, Intermediate, and College Algebra: One Step at a Time." You may need to see Basic Algebra in Chapter 5, or click on Intermediate Algebra and choose Chapter 3. Explanation varies in level of difficulty between these two. If you want College Algebra, go to the MATH IN LIVING COLOR pages, and Choose College Algebra, Chapter 1.

R^2

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