SOLUTION: If f(x) = x^2, find f(8-square root 5)
=(8-sq. root 5)(8- sq. root 5)
=8^2-8(sq. root 5)-8(sq. root 5)+(sq. root 5)^2
=64-16 sq. root 5+5
=64+5-
Algebra.Com
Question 136420: If f(x) = x^2, find f(8-square root 5)
=(8-sq. root 5)(8- sq. root 5)
=8^2-8(sq. root 5)-8(sq. root 5)+(sq. root 5)^2
=64-16 sq. root 5+5
=64+5-16 sq. root 5
=69-16 square root 5
Answer by tns_tutor5000(9) (Show Source): You can put this solution on YOUR website!
RELATED QUESTIONS
Simplify:
3 sq root 32 - 5 sq root 50 - 8 sq root 45 + 7 sq root 20
(answered by checkley77)
3 SQ. ROOT OF 8 + 2 SQ. ROOT OF... (answered by kara!)
Simplify:
5 - sq root 2/sq root... (answered by stanbon)
f(x)= sq root... (answered by haileytucki)
another problem:
sq root of x-2 divided by sq root of... (answered by funmath)
Please show how to work out:
6 the sq root of 20 plus 8 the sq root of 5 minus 5 the sq (answered by Alan3354)
8 with an exponent of 4/3
Cubed sq root of 5 over cubed sq. root over... (answered by stanbon)
sq. root of 3/5
sq. root of 3 13/3
sq. root of 3{2}+5{2}
sq. root of m^2/n^3... (answered by checkley75)
sq root(x^2+5)=x+3
Thank... (answered by stanbon)