SOLUTION: Help me please. It asks to solve by completing the square.
x^2-x-1=0
What I got for that was (y=a) (a=1) (H=1/2) and (k=5/4)
I am not sure if they are correct or not, please hel
Algebra.Com
Question 136355: Help me please. It asks to solve by completing the square.
x^2-x-1=0
What I got for that was (y=a) (a=1) (H=1/2) and (k=5/4)
I am not sure if they are correct or not, please help,Thank You=)
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
Help me please. It asks to solve by completing the square.
x^2-x-1=0
What I got for that was (y=a) (a=1) (H=1/2) and (k=5/4)
I am not sure if they are correct or not, please help,Thank You=)
Get rid of the constant term on the left by adding
to both sides:
Multiply the coefficient of x on the left, which is by , getting .
Now square .
Now add to both sides:
write the as
The LCD on the right is , so multiply by
Now factor the left side:
The left side is a perfect square (that's why the method is
called "completing the square"). So we write the left side
as a square, the square of a binomial:
Next we use the principle of square roots:
= ±
= ±
= ±
Now we solve for x by adding to both sides:
=
=
Edwin
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