SOLUTION: sqrt T + 12 - T = 0 T+12-T=0 sqrt(T+12)-T=0 sqrt(T+12)=X (sqrtT+12)^2=T^2 T+12=T^2 T^2-T-12=0 I came up with (T = 4)(T-3) and I don't if I'm right please help!

Algebra ->  Algebra  -> Radicals -> SOLUTION: sqrt T + 12 - T = 0 T+12-T=0 sqrt(T+12)-T=0 sqrt(T+12)=X (sqrtT+12)^2=T^2 T+12=T^2 T^2-T-12=0 I came up with (T = 4)(T-3) and I don't if I'm right please help!      Log On

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Question 136313: sqrt T + 12 - T = 0

T+12-T=0
sqrt(T+12)-T=0
sqrt(T+12)=X
(sqrtT+12)^2=T^2
T+12=T^2
T^2-T-12=0

I came up with (T = 4)(T-3) and I don't if I'm right please help!
Answer by oscargut(686) About Me  (Show Source):
You can put this solution on YOUR website!
if equation is:
sqrt (T + 12) - T = 0 (eq 1)
then you did it well and
T^2-T-12=0 (eq 2)
T=4 and T=-3
but solutions of the (eq 1) are included in solutions of (eq 2)
(-3 is a solution of the eq 2 but not a solution of eq 1)
Answer: T=4