SOLUTION: divide: 4-2i over 3+5i

Question 135613: divide:
4-2i over 3+5i
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The first thing you need to do is rationalize the denominator. To rationalize a denominator containing an irreduceable binomial, multiply the entire fraction by 1 in the form of the conjugate of the denominator divided by itself.

If you have a complex number of the form , the conjugate is .

The product of the denominators will then be a single rational number because the product of and is (assuming rational coefficients a and b in the complex number).

Now use FOIL to multiply numerator times numerator, and use the reverse of the difference of two squares factorization to multiply denominator times denominator. Then collect like terms. If your result has a common integer factor in both numerator and denominator, take that out.

RELATED QUESTIONS
divide: 4-2i over... (answered by stanbon)

(3+2i)(4-5i) (answered by robertb)

Simplify:... (answered by Fombitz)

(2-3i)-(4-5i)+(-3+2i) (answered by jsmallt9)

(5i-3)(2i-3)= (answered by drk)

(4+2i)-(-1+5i) (answered by jim_thompson5910)

-1 + 5i ________ 3 +... (answered by rapaljer)

3-5i/5+2i (answered by lynnlo,MathTherapy)

(3-2i)(6+5i) (answered by stanbon,Earlsdon,algebrahelp101)