# SOLUTION: Can anyone help me solve this equation? 160x=3x + the sqaure root of 50x+9000 160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides

Algebra ->  Algebra  -> Radicals -> SOLUTION: Can anyone help me solve this equation? 160x=3x + the sqaure root of 50x+9000 160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Radicals -- complicated equations involving roots Solvers Lessons Answers archive Quiz In Depth

 Question 124427: Can anyone help me solve this equation? 160x=3x + the sqaure root of 50x+9000 160x-3x=the square root of 50x + 9000 is all the farther I've gotten. I think I square both sides now to get rid of the square root symbol, but do I need to simplify it first and if so, how?Answer by ankor@dixie-net.com(15656)   (Show Source): You can put this solution on YOUR website!160x=3x + the sqaure root of 50x+9000 : 160x-3x=the square root of 50x + 9000 which is: 157x = sqrt(50x+9000) : Square it: 24649x^2 = 50x + 9000 : Arrange as a quadratic equation 24649x^2 - 50x - 9000 = 0 : you have to use the quadratic formula to solve it: In this equation a=24649; b=-50; c=-9000 : : : Two solutions: x = +.605 and x = -.603 : I checked these solutions on a Ti83 graphing calc. You can confirm it yourself by substitution in the original equation