SOLUTION: P1=(2,-5) P2= (5,4) d(P1,P2)= answer using radical as needed

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Question 121916: P1=(2,-5)
P2= (5,4)
d(P1,P2)=
answer using radical as needed
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Do you want to find the distance between these points?

Start with the given distance formula
d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29 where is the first point and is the second point

d=sqrt%28%282-5%29%5E2%2B%28-5-4%29%5E2%29 Plug in x%5B1%5D=2, x%5B2%5D=5, y%5B1%5D=-5, y%5B2%5D=4

d=sqrt%28%28-3%29%5E2%2B%28-9%29%5E2%29 Evaluate 2-5 to get -3. Evaluate -5-4 to get -9.

d=sqrt%289%2B81%29 Square each value

d=sqrt%2890%29 Add

d=3%2Asqrt%2810%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)


So the distance approximates to

d=9.48683298050514

which rounds to
9.49

So the distance between (2,-5) and (5,4) is approximately 9.49 units