SOLUTION: Find the real solutions by factoring. x^2 + sqrt{3}x^2 - 3 = 0 Let x^4 = (x^2)^2 Let u = x^2 u^2 + sqrt{3}x

SOLUTION: Find the real solutions by factoring. x^2 + sqrt{3}x^2 - 3 = 0 Let x^4 = (x^2)^2 Let u = x^2 u^2 + sqrt{3}x - 3 = 0 Stuck here.... Can I use the q

Question 1207666: Find the real solutions by factoring.

x^2 + sqrt{3}x^2 - 3 = 0

Let x^4 = (x^2)^2

Let u = x^2

u^2 + sqrt{3}x - 3 = 0

Stuck here....

Can I use the quadratic formula?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.


Your starting equation is THIS

     +  - 3 = 0.


It is the same as

     +  = 3.


Factor left side

     = 3.


Divide both sides by    and express x^2 explicitly

    x^2 = .


Get rid of irrationality in the denominator

    x^2 =  =  =  = .


Now take square root of both sides and find x

    x =  = 1.047891...


ANSWER.  x =  = 1.047891  (rounded).

Solved.

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