SOLUTION: Hi Tutors, Can someone see if I did this problem right and if not can you tell me what I did wrong. Solve the equations. sqrt 4x + 1 + 3 =0 sqrt 4x + 1 = -3 sqrt 4x + 1

Question 119883: Hi Tutors, Can someone see if I did this problem right and if not can you tell me what I did wrong. Solve the equations.

sqrt 4x + 1 + 3 =0
sqrt 4x + 1 = -3
sqrt 4x + 1^2 =(-3)^2
4x + 1= 9
4x = 9 � 1 Subtract
4x = 8 Divide by 2
x= 2 is the answer
How can I check to see if this is the right answer.

One more thing I am stuck on this problem because of the x can someone please help.
sqrt 2x + 1 + x = 7
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Subtract
Divide by 2
is the answer
How can I check to see if this is the right answer.
You can plug this value of back into the original equation,
but first notice what you got above:

This is telling you that what you're squaring on the right is
a negative number, so The square root on the left must be the
negative square root, which, when squared gives a positive
Going back to:

This is true, one of the square roots of 9 is -3.

OK
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