SOLUTION: I'm on radical Quotient property. I'm trying to understand where my tutorial is getting x over y = xy^-1 kind of like cubic root of x^2 * y over cubic root of 8*x*y^2 w

Algebra.Com
Question 1194326: I'm on radical Quotient property. I'm trying to understand where my tutorial is getting x over y = xy^-1
kind of like
cubic root of x^2 * y over
cubic root of 8*x*y^2
which is rewritten as the cubic root of the entire fraction by applying
Quotient property
similar to
Cubic root of
x^2*y over
8*x*y^2
1 of the x's and 1 of the y's cancel each other out because exponent's Quotient property
so now we have
Cubic root of
x over
8y
now we apply Product Property and get
cubic root of
1 over 8 * x over y
I understand 1*x=x and 8*y=8y but here is where my tutorial loses me. They have
cubic root of 1 over cubic root of 8 * cubic root of xy^-1
the explanation is "Quotient property and x over y = xy^-1"
this makes no sense to me. Is this just a fact?
they then rewrite
cubic root of
1 over 8 * x over y
again saying "Quotient property and x over y = xy^-1"
finally
1 over 2 cubic root xy^-1 "Our solution"

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
Maybe I not follow your description well but x/y means the same as x*y^(-1). This is well defined notation and not a mystery.


"cubic root of
1 over 8 * x over y"
That is ambiguous.


"cubic root of x^2 * y over
cubic root of 8*x*y^2"
Again this is also ambiguous.


-----------

I saw and read your extra note. Most of the square root description is still too ambiguous. Show your starting expression clearly in correct notation to get the help you want.

As for , this is already clear. Nothing to not understand.

---

Is this what your expression is as given?



And if so, you wish to simplify this?

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

I'm on radical Quotient property. I'm trying to understand where my tutorial is getting x over y = xy^-1
kind of like
cubic root of x^2 * y over
cubic root of 8*x*y^2
which is rewritten as the cubic root of the entire fraction by applying
Quotient property
similar to
Cubic root of
x^2*y over
8*x*y^2
1 of the x's and 1 of the y's cancel each other out because exponent's Quotient property
so now we have
Cubic root of
x over
8y
now we apply Product Property and get
cubic root of
1 over 8 * x over y
I understand 1*x=x and 8*y=8y but here is where my tutorial loses me. They have
cubic root of 1 over cubic root of 8 * cubic root of xy^-1
the explanation is "Quotient property and x over y = xy^-1"
this makes no sense to me. Is this just a fact?
they then rewrite
cubic root of
1 over 8 * x over y
again saying "Quotient property and x over y = xy^-1"
finally
1 over 2 cubic root xy^-1 "Our solution"
This is EXACTLY how itw's done:

RELATED QUESTIONS

can u help me on this hehe i need 3 examples of every law of exponents(FIRST TO FOURTH... (answered by josgarithmetic)
can you help me on this hehe i need 3 examples of every law of exponents(FIRST TO FOURTH... (answered by Solver92311)
can u help me on this hehe i need 3 examples of every law of exponents(FIRST TO FOURTH... (answered by Solver92311)
I am trying to solve the problem 4m/7 + m =11 and am getting no where with my answer.... (answered by edjones,stanbon)
If m(x) = -2x+1, what is [m(x+2) - m(x)]/2? The answer is said to be -2 but I keep on... (answered by Alan3354)
I hope this is the right category. I wasn't sure where to put it. The beginning intro to... (answered by scott8148)
im doing "zero and negaive exponents"... in need to "use the quotient of powers property (answered by wuwei96815)
im doing "zero and negaive exponents"... in need to "use the quotient of powers property (answered by wuwei96815)
I'm trying to create a system of linear equations using my running habbits. I run 2... (answered by josmiceli)