SOLUTION: For what values of c will x² +28x + c = 0 have no real solutions? Explain

Question 1179144: For what values of c will x² +28x + c = 0 have no real solutions? Explain
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x² +28x + c = 0
comparing with ax2+bx+c=1

a=1, b=28 , c=1
b^2 -4ac = 28^2 - 4*1*1
784/4 = 196
c>196
For no real solutions b^2-4ac <0

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

For what values of will have solutions? Explain

use discriminant to find

recall, if , there will be solutions
in your case , , and
then

or

check: let

using calculator we get
Complex solutions:

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