SOLUTION: Find the domain of the function f(x) = sqrt of 4x-32 What is the domain in interval notation?

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Question 1163827: Find the domain of the function
f(x) = sqrt of 4x-32
What is the domain in interval notation?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you meant to say f%28x%29+=+sqrt%284x-32%29, then we want the stuff under the square root to be either 0 or positive. Taking the square root of a negative number leads to a non-real result.

Set the radicand 4x-32 to be greater than or equal to 0. Isolate x.

4x-32+%3E=+0

4x-32%2B32%3E=0%2B32 Adding 32 to both sides

4x%3E=32

4x%2F4%3E=32%2F4 Dividing both sides by 4

x%3E=8

The domain is any number x such that x+%3E=+8. So x = 8 or x is larger than 8.

To write this in interval notation, we will say [8, infinity) where you'll replace the word "infinity" with the infinity symbol. This is the interval from 8 to infinity. We include 8 through the use of the square bracket. The curved parenthesis is always used with infinity because we can't reach infinity (its not a number).


Answer: [8, infinity)