SOLUTION: m = (1/3)(xy)^2
I'm solving for x
m = 1/3(x^2^y2)
m = x^2y^2/3
3m = x^2y^2
3m/y^2 = x^2
±√3m/y^2 = x >>>> or is it ±√3m/y = x, this is my problem
±3^1
I'm solving for x
m = 1/3(x^2^y2)
m = x^2y^2/3
3m = x^2y^2
3m/y^2 = x^2
±√3m/y^2 = x >>>> or is it ±√3m/y = x, this is my problem
±3^1/2m^1/2/(y^2)^1/2 = x
±3^1/2m^1/2/y = x
±√3m/y = x
If this is the correct answer, how is the next step?
It's usually best and easiest to clear of fractions first:
Clear the fraction by multiplying both sides by 3
Use the principle of square roots:
Divide both sides by y:
Edwin