SOLUTION: {{{square root of k+2 - square root of k-3 =1}}}
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Question 114646This question is from textbook introductory and intermediate algebra
:
This question is from textbook introductory and intermediate algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
square root of k+2 - square root of k-3 =1
sqrt(k+2) = sqrt(k-3) + 1
Square both sides to get:
k+2 = (k-3)+2sqrt(k-3)+1
4 = 2sqrt(k-3)
sqrt(k-3) = 2
Square both sides:
k-3 = 4
k = 7
------------
Checking in the original equation:
sqrt(9) - sqrt(4) = 1
3-2 = 1
=============
Cheers,
Stan H.
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