SOLUTION: what am i doing wrong? � = 3 � (2x-1)/(x+2) � * 4(x+2) = 3 � {(2x-1)/(x+2)} *4(x+2) x + 2 = 3 � (2x � 1)4 x + 2 = 3 � (8x � 4) x + 2 = 7 � 8x x + 2 � 2 = 7 � 2 � 8x x +8x =

Question 113393: what am i doing wrong?
� = 3 � (2x-1)/(x+2)
� * 4(x+2) = 3 � {(2x-1)/(x+2)} *4(x+2)
x + 2 = 3 � (2x � 1)4
x + 2 = 3 � (8x � 4)
x + 2 = 7 � 8x
x + 2 � 2 = 7 � 2 � 8x
x +8x = 7 � 8x +8x
9x = 7
9x/9 = 7/9
x = 7/9

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
� = 3 � (2x-1)/(x+2)
x+2=12(x+2)-4(2x-1) multiply each side by 4(x+2) to eliminate fractions. You didn't multiply 4(x+2) by the 3.
x+2=12x+24-8x+4
-3x=26
x=-26/3 divide each side by -3.
Ed
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