SOLUTION: How do I solve -25^-3/2 ? I also need to solve 3/3 multiply by 4/2 using the following principal root product rule quotient rule reciprocal nth root?
Question 1092978: How do I solve -25^-3/2 ? I also need to solve 3/3 multiply by 4/2 using the following principal root product rule quotient rule reciprocal nth root? Found 2 solutions by addingup, MathTherapy:Answer by addingup(3677) (Show Source): You can put this solution on YOUR website! I'll help you with the first one
-25^(-3/2)
rewrite as follows:
(-1)/(25^(3/2))
Let's separate the exponent of 25^(-3/2) into integer and fractional parts, like this 25^(-3/2) = 25^(1/2 - (4)/2) = 25^(-4/2)×sqrt(25):
-25^(-4/2)sqrt(25)
= -25^(-2)sqrt(25)
Evaluate 25^2.
| 2 | 5
× | 2 | 5
1 | 2 | 5
5 | 0 | 0
6 | 2 | 5:
-(sqrt(25))/(625)
Let's simplify, like this sqrt(25) = sqrt(5^2) = 5:
-5/625
Divide both numbers by 5 to get your answer:
(-1)/125 Answer by MathTherapy(10553) (Show Source): You can put this solution on YOUR website! How do I solve -25^-3/2 ? I also need to solve 3/3 multiply by 4/2 using the following principal root product rule quotient rule reciprocal nth root?
There''s nothing to solve here since this is NEITHER an equation nor an inequality.
Instead, it can be simplified as follows: =====> =====> ====> =====>