SOLUTION: I have to solve this factoring problem : 6x^4-10x^3-6x^2 the # after the ^ is the exponents I found a GCF of 2x^2 and left off at: 2x^2(3x^2-5x-3) I did x+x=b which is -5 a

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Question 1069316: I have to solve this factoring problem :
6x^4-10x^3-6x^2
the # after the ^ is the exponents
I found a GCF of 2x^2 and left off at:
2x^2(3x^2-5x-3)
I did x+x=b which is -5
and x*x=ac which is -9
so what two numbers would added give me -5 but multiplied give me -9?
Thats as far as i got. Please help me
Thanks
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Common factor, ;


Discriminant?
, not a perfect square.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I have to solve this factoring problem :
6x^4-10x^3-6x^2
the # after the ^ is the exponents
I found a GCF of 2x^2 and left off at:
2x^2(3x^2-5x-3)
I did x+x=b which is -5
and x*x=ac which is -9
so what two numbers would added give me -5 but multiplied give me -9?
Thats as far as i got. Please help me
Thanks 
Good job!! You're correct up to here =======> 

I see you tried to find factors with a product of - 9, and that sum to - 5 (ac method).

Those integers do not exist, so this is where the factoring ends, as it cannot be factored further. 

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