SOLUTION: Please explain how to solve Sqrt 5x+1-4 = 0. I get the following; sqrt 5x+1-4=0 sqrt 5x-3=0 5x-3=0^2 5x-3=0 5x-3+3=0+3 5x=3 5x/5 = 3/5 x=3/5 Thank you.

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Question 1069137: Please explain how to solve
Sqrt 5x+1-4 = 0.
I get the following;
sqrt 5x+1-4=0
sqrt 5x-3=0
5x-3=0^2
5x-3=0
5x-3+3=0+3
5x=3
5x/5 = 3/5
x=3/5
Thank you.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
First thing is to write it correctly, in an understandable format.

For it, use PARENTHESES.

Otherwise nobody understand how far your square root does extend.



Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Please explain how to solve
Sqrt 5x+1-4 = 0.
I get the following;
sqrt 5x+1-4=0
sqrt 5x-3=0
5x-3=0^2
5x-3=0
5x-3+3=0+3
5x=3
5x/5 = 3/5
x=3/5
Thank you.
No-one can unless you can state whether it's: . 

I kind of doubt it's:  

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