SOLUTION: Rationalize the denominator. (3√10)/(2+√10) I so far got... (3√10)/(2+√10) * (2-√10)/(2-√10) [(3√10)(2+√10)]/(2)^2+(√10)^2

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Question 1058504: Rationalize the denominator.
(3√10)/(2+√10)
I so far got...
(3√10)/(2+√10) * (2-√10)/(2-√10)
[(3√10)(2+√10)]/(2)^2+(√10)^2
[(6√10)-(3√100)]/4-10
Then I get stuck.
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!


The conjugate of the DENOMINATOR is . Multiply the rational expression (the ENTIRE fraction) by 1.


Simplify that.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Rationalize the denominator.
(3√10)/(2+√10) 

I so far got...

(3√10)/(2+√10) * (2-√10)/(2-√10)     - Correct

[(3√10)(2+√10)]/(2)^2+(√10)^2        - Wrong //  Must be 

[(6√10)-(3√100)]/4-10                - Correct.

Now replace by 10 and replace (4-10) by (-6).


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Rationalize the denominator.
(3√10)/(2+√10)
I so far got...
(3√10)/(2+√10) * (2-√10)/(2-√10)
[(3√10)(2+√10)]/(2)^2+(√10)^2
[(6√10)-(3√100)]/4-10
Then I get stuck. 
 <======= You're up to here

 -------- Simplifying 



 ------- Factoring NUMERATOR

 ------ Canceling - 6 in NUMERATOR and DENOMINATOR

 

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