SOLUTION: Rationalize the denominator (√ 7)/(√ 3+2) I got as far as (√ 7)/(√ 3+2) * (√ 3-2)/(√ 3-2) [(√ 7)(√ 3+2)]/(√ 3)^2-(2)^2

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Question 1058454: Rationalize the denominator
(√ 7)/(√ 3+2)
I got as far as
(√ 7)/(√ 3+2) * (√ 3-2)/(√ 3-2)
[(√ 7)(√ 3+2)]/(√ 3)^2-(2)^2
[(√ 7)(√ 3+2)]/3+4
[(√ 7*√3)-(2√2)]/7
[(√21)-(2√2)]/7
My book is saying that the answer is (√21)-(2√2) Without a denominator. Did I do something wrong or is the book wrong (it's been wrong before).
Found 3 solutions by Fombitz, Alan3354, Edwin McCravy:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Your denominator should be not

Final answer should be,
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!

=
= You had 3+4
=
=
============
The book is also wrong.

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
Looks like you made a sign error, 3+4 should have been 3-4.
Multiply the bottoms using FOIL







Use FOIL in the denominator:



[That was where you made your error]















Yes the book is wrong!

Edwin
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