SOLUTION: 1. Solve sqrt2x + x = 4 for x. Answers: A. x = 2 B. The two solutions are for complex numbers. C. x = 2 or x = 8 ( I picked C and it was wrong) D. x = 4 or x = -4 Thank Yo

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Question 1019621: 1. Solve sqrt2x + x = 4 for x.
Answers: A. x = 2 B. The two solutions are for complex numbers.
C. x = 2 or x = 8 ( I picked C and it was wrong) D. x = 4 or x = -4
Thank You.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39615)   (Show Source): You can put this solution on YOUR website!
Your text is not well written so one could guess you have sqrt(2x)+x=4, which would best appear .

Isolate the radical.


Square the equated members.


Simplify and solve.



and if you check you find both x=2 and x=8 will work.
x=2 OR x=8.

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

1. Solve sqrt2x + x = 4 for x.
Answers: A. x = 2 B. The two solutions are for complex numbers.
C. x = 2 or x = 8 ( I picked C and it was wrong) D. x = 4 or x = -4
Thank You.
This appears to be . If so, the answer CANNOT be C, but: , instead.
Why don't you use parentheses, or provide info to make this problem less ambiguous? Is that so difficult?
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