SOLUTION: Solve for x: 2x+7[sqrt(x)]-15=0
Algebra.Com
Question 1017937: Solve for x: 2x+7[sqrt(x)]-15=0
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
Let sqrt(x) = a.
2a^2 + 7a - 15 = 0
(2a-3)(a+5) = 0
a = 3/2 and a = -5.
One solution is extraneous: (a cannot be negative)
a = 3/2, so x = 9/4
RELATED QUESTIONS
Solve for x: sqrt(2x-1) - sqrt(x+3) =... (answered by funmath)
Solve for x
sqrt( 2x-3)=sqrt(x)+5
(answered by stanbon)
Solve
sqrt 2x + 15 = x +... (answered by MathLover1,mgmoeab)
sqrt 2x+7 - sqrt x+7 = 1
(answered by stanbon)
solve for x
sqrt( x^2 -2x) = x-4 (answered by stanbon,MathTherapy,Alan3354)
Solve for x;
{{{sqrt(3x)+sqrt(2x-1)= 5/(sqrt(2x-1))}}} (answered by cigany29)
Solve
If f(x)={{{sqrt(2x-3)}}} and g(x)={{{sqrt(x+7)}}}-2,find any x for which... (answered by MathLover1)
solve for x
sqrt x+7+5=... (answered by solver91311)
solve for... (answered by Fombitz)