SOLUTION: For i = the square root of -1, if 3i (2 + 5i) = x + 6i, then x = ?

Algebra.Com
Question 1009310: For i = the square root of -1, if 3i (2 + 5i) = x + 6i, then x = ?
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
For 3i(2 + 5i) = x + 6i, we have
3i(2 + 5i) = 6i + 15i^2 = -15 + 6i
so x = -15

RELATED QUESTIONS

for i= square root -1, if 3i(2+5i)=x+6i, then... (answered by venugopalramana)
For i= square root -1, if 3i(2+5i) = x+6i, then x =... (answered by QH)
i=square root of -1 if 3i(2+5i)=x+6i, then... (answered by ReadingBoosters)
For i = the square root of -1, if 3i (2 + 5i) = x + 6i, then x = ? A. –15 B. 5 C.... (answered by stanbon,josgarithmetic)
How do you solve this problem step by step? For i = square root of -1, if 3i(2 + 5i)=... (answered by ankor@dixie-net.com)
For i = , if 3i (2 + 5i) = x + 6i, then x =... (answered by nyc_function)
I have a question. For i= the square root of -1, if 3i(2+5i) = x+6i, then x = A. -15 (answered by josmiceli)
For i =square root −1, if 3i(2 + 5i) = x + 6i,then x = ? A. –15 B. 5 C. 5i (answered by jim_thompson5910)
For i= √-1, if 3i(2+5i)= x+6i, then x= (answered by vleith)