Tutors Answer Your Questions about Radicals (FREE)
Question 571248: Suppose that a cylinder has a volume of 314 in^3 and a radius of 5 in. Find the height of the cylinder. Use pie symbol = 3.14. Here is the given equation,h= Vr^-2/3.14 I know we plug in 314in^3 for V and 5 for r, so h=3.14^3(5^-2)/3.14 The exponents are throwing me off with this equation....Please help me understand this, it is due today. Thank you
Click here to see answer by scott8148(5879)  |
Question 568317: g(x) = sqrt( -x) I know that that is an imaginary number. I understand that when y = 3, then x = -9. When y = 2, then x = -4, when y = 1, then x = -1. But what is the algebraic process to get those neg x values?
Click here to see answer by Theo(2967)  |
Question 566930: Please help me solve this equation: .
what i have tried is squaring both sides to where i get
the i subtracted the 
the answer i got was but my teacher said it was wrong
he has said the correct answer is what did i do wrong?
Click here to see answer by richard1234(4789)  |
Question 566232: Explain the difference between rationalizing the denominator in an algebraic expression whose denominator has only one term involving a radical and one whose denominatror has two terms, at least one of which involves a radical.
Click here to see answer by lwsshak3(2907) |
Question 561329: sqrt(x-6)+3=sqrt(x)
does this have a real solution?
first i subtracted the 3 over, squared both sides and ended up with x=(25/4) but when i plug that in, it was not a true statement.
then i started over and squared both sides like the original problem shows and got the square root equal to a negative so that would be "no real solution".
thank you for looking at this!!
Click here to see answer by scott8148(5879)  |
Question 561329: sqrt(x-6)+3=sqrt(x)
does this have a real solution?
first i subtracted the 3 over, squared both sides and ended up with x=(25/4) but when i plug that in, it was not a true statement.
then i started over and squared both sides like the original problem shows and got the square root equal to a negative so that would be "no real solution".
thank you for looking at this!!
Click here to see answer by jim_thompson5910(21667) |
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