# SOLUTION: Can you help me find the x-intercepts?? y=x^2+6x+8 and y=x^2-2x+4 Thanks for your help! CH

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 Question 60788: Can you help me find the x-intercepts?? y=x^2+6x+8 and y=x^2-2x+4 Thanks for your help! CHAnswer by funmath(2926)   (Show Source): You can put this solution on YOUR website!Hi CH find the x-intercepts?? y=x^2+6x+8 and Let y=0 and solve for x. 0=x^2+6x+8 Factor 0=(x___)(x___) the blank gets filled with two numbers that multiply to get 8 and add to get 6. 2*4=8 and 2+4=6 0=(x+2)(x+4) Let each parentheses=0 x+2=0 and x+4=0 x=-2 and x=-4 The x-intercepts are (-2,0) and (-4,0) : y=x^2-2x+4 This has no x-intercepts. It's not factorable. If you're familiar with the discriminant:, you can tell if a quadratic equation has no x-intercepts if the discriminant is negative. There are no x-intercepts. Happy Calculating!!!