# SOLUTION: Find the maximum or minimum value of the function. f(x)= -x^2/3+2x+6 (it's -x^2 over 3 then +2x+6) I thought that you have to use -b/2a and then f(x)=-b/2a

Algebra ->  -> SOLUTION: Find the maximum or minimum value of the function. f(x)= -x^2/3+2x+6 (it's -x^2 over 3 then +2x+6) I thought that you have to use -b/2a and then f(x)=-b/2a       Log On

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 Click here to see ALL problems on Quadratic Equations Question 411199: Find the maximum or minimum value of the function. f(x)= -x^2/3+2x+6 (it's -x^2 over 3 then +2x+6) I thought that you have to use -b/2a and then f(x)=-b/2a Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Find the maximum or minimum value of the function. f(x)= -x^2/3+2x+6 (it's -x^2 over 3 then +2x+6) ---- a = (-1/3) ; b = 2 ; c = 6 ---- I thought that you have to use -b/2a and then f(x)=-b/2a Max or min occurs at x = -b/(2a) = -2/(2*(-1/3)) = -2/(-2/3) = 3 ---- f(3) = (-1/3)(3^2) + 2(3) + 6 = -3+6+6 --- = 9 =========== Cheers, Stan H. ===========