# SOLUTION: Hi, I am looking for some help! I need to show my work, (all steps I took to obtain the answer, but I have no idea how to complete the problem. Could someone please help me? (secti

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 Question 361324: Hi, I am looking for some help! I need to show my work, (all steps I took to obtain the answer, but I have no idea how to complete the problem. Could someone please help me? (section 11.1, #7) Directions: Solve each equation by the square root property. If possible, simplify radicals or rationalize denominators. Express imaginary solutions in the form a +bi. 〖3x〗^2-2=0 (the first part should be 3x (squared) but for some reason it's not showing that way). If you can show me the steps and how to obtain the answer that is: {±√6/3}Found 2 solutions by stanbon, Alan3354:Answer by stanbon(60772)   (Show Source): You can put this solution on YOUR website!Solve each equation by the square root property. If possible, simplify radicals or rationalize denominators. Express imaginary solutions in the form a +bi. 〖3x〗^2-2=0 (the first part should be 3x (squared) but for some reason it's not showing that way). If you can show me the steps and how to obtain the answer that is: {±√6/3} ------- 9x^2 - 2 = 0 (2--- 9x^2 = 2 Take the square root of both sides to get: 3x = sqrt(2) or 3x = -sqrt(2) --- x = (1/3)sqrt(2) or x = (-1/3)sqrt(2) ------------------------------------------ Cheers, Stan H. Answer by Alan3354(34677)   (Show Source): You can put this solution on YOUR website! --------------- -------------------- I don't see a sqrt(6)