Question 249634: The length of a rectangle is 1cm more than twice the width. If the area is 78cm (squared). Find the dimensions. I came up with this so far?
2w(squared)+w - 78 = 0
I factored that as (2w + 13) and (2w - 6) = 0
But then I would be getting W = -13/2 and W = 6
Am I on the right track? I'm supposed to be finding the dimensions of the rectangle.
Thanks Answer by richwmiller(10275) (Show Source):
You can put this solution on YOUR website! L=2w +1
this is good
divide by 2
[how did you get (2w + 13) and (2w - 6)
I see the 78 but where is the w?
I get 26w-12w=14w not 1w
to factor you need factors of 78 with a difference of one.
there aren't any whole numbers]
complete the square
add 1/16 to both sides
we can't use the negative solution so we have 6 for w